# A golf ball is hit at an angle of 45 above the horizontal

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• A golfer hits a golf ball at an angle of 25 degrees to the ground. If the golf ball covers a horizontal distance of 301.5m, what is the ball's maximum height? (At the top of its flight, the balls vertical velocity component will be zero.)
• A golf ball is hit and an angle of 45° above the horizontal. What is the acceleration of the golf ball at the highest point it's trajectory? 9.8 m/s squared downward THIS SET IS OFTEN IN FOLDERS WITH...
• 3. A batter hits a ball with an initial velocity of 92 feet per second and at an angle of 55 o from the horizontal. Find the maximum height attained and the total horizontal distance traveled by the ball. The maximum height reached is about 88.7 ft and the horizontal distance traveled is about 249 ft.
• 12) A golf ball is hit at an angle of 45° above the horizontal. What is the acceleration of the golf ball at the highest point in its trajectory? [Neglect friction.] (A) 9.8 m/s 2 upward (B) 9.8 m/s 2 downward (C) 6.9 m/s 2 horizontal (D) 0.0 m/s 2
• Sep 01, 2009 · To solve the problem, they hit in the area located above the sweet spot, known by some as the hot zone. The hot zone knocks rpms off the hit and sends the ball away on a higher trajectory for more penetrating and straighter shots. Give it a try and see if you can hit the hot zone.
• Oct 30, 2017 · A golf ball is hit with an initial velocity of 140 ft per second at an inclination of 45 degrees to the horizontal. In​ physics, it is established that the height h of the golf ball is given by the function h (x)=-32x^2/140^2+x,
• Three identical balls are launched with the same initial speed from the top of a cliff. Ball A is launched horizontally. Ball B has an initial velocity directed 20 degrees below the horizontal. Ball C has an initial velocity directed 40 degrees above the horizontal. Which ball hits the ground with the highest speed? Ball A Ball B Ball C
• The lower launch and lower spin rate from the 44.5” driver created a more penetrating (flatter) ball flight. The angle of decent with the 44.5” driver, which is the angle the ball approaches the ground, was 1.3 degrees flatter than the 45.5” driver which means the ball will roll out more once it hits the ground.
• a ball hit from a height of 1.0 m, at 30 m/s and at various angles to the horizontal, including the effects of air resistance. In order to just clear the net, a ball hit without spin must be hit upwards at 4.0o to the horizontal. If the ball has topspin at 20 revolu-tions/sec, it must be hit upwards at 5.5o to the horizontal. If a ball is hit
• Oct 21, 2018 · 2.A ball on a table of height h is rolled off a table traveling at velocity v, neglecting air resistance how much time does it take for the ball to hit the ground? A) 2.5 m/s B) 4.3 m/s C) 5.0 m/s D) 10 m/s E) 20 m/s 3.A basketball is thrown upwards on an arc at a 60 degree angle with the horizontal.
• Approaching the Ball and Preparing to Shoot. Pre-shot preparation involves approaching the ball from the correct angle, planting your non-shooting foot and moving your shooting leg into position. If possible, approach the ball at a 45-degree angle relative to a direct line between the ball and your target.
• Suppose you take a ball and launch it from the ground with an initial velocity that is some angle above the horizontal (call that angle θ). After the ball leaves the launcher (or whatever got it ...
• Set up the launcher at a 25 ° angle with the horizontal such that the bottom of the launch position (circle drawn on end of launcher) is at table-top height, as shown below Lay out the paper and carbon paper similar to Part II. Shoot the ball and measure the "range" R, the distance from the launch position to landing position. Repeat twice more.
• Aug 20, 2014 · Tee a ball as normal and then stick a shaft in the ground at a 45-degree angle to the ground, approximately 1-1/2 to 2 feet behind the ball and 6 inches outside of the target line (i.e., farther...
• A golf ball is hit with an initial velocity of 130 feet per second at an inclination. of 45 to the horizontal. In physics, it is established that the height h of the golf ball is given. by the function. h (x) = − (32/130^2)x^2 + x.
Linux flr appliance deploy failed failed to connect backup datastore to the esx hostFind the perfect Golf Ball stock photos and editorial news pictures from Getty Images. Select from premium Golf Ball of the highest quality. A baseball hit at 103 mph at 28.3* above the horizantle will travel about 403 feet with an average apex of 91ft high. Your equations are correct, but not applied properly. A good source of comparison is hittrackeronline.com .
A rating of a golf club shaft's ability to bend during the golf swing. The faster the swing speed, the stiffer the flex should be. Shot Dispersion: Describes the final position of multiple golf balls hit from the same spot. Balls covering a large area are said to have a wide dispersion, while tightly clustered golf balls have a narrow dispersion.
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• Drivers are designed to maximize the ball's carry distance, so a driver's loft angle ranges from 8 to 13 degrees, depending on the specific brand or model of driver. Woods, ranging from a 2-wood to a 5-wood are also used for distance, but their loft angle is slightly greater than a driver. This angle provides the golfer with distance, with a ... Simply utilize your knowledge of the D-Plane as you swing on a Driver horizontal swing plane of 45 degrees, while controlling your Angle of Attack, Club Swing Path, Clubface Orientation at Impact to create the perfect Horizontal and Vertical Launch conditions with just the right spin loft & spin axis to hit a perfectly straight shot!
• The launching angle θ = 45 degrees and the range is 180.0 m. H is the maximum height in meters and g = 9.8 m/s^2. Using the range formula you can solve for the initial velocity Vi or Vo by fitting in the given values. 180.0 m = Vi^2 * sin (2 * 45) / 9.8 m/s^2. Vi^2 = 180.0 /sin 90/9.8.
• When the ball has traveled a horizontal distance of 39.6 m, it is 16.8 m above the ground. The goal posts are 3.10 m high; so the ball clears the goal posts by 13.7 meters. (b) Part b of this problem can be done in a similar manner.

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Sep 01, 2009 · To solve the problem, they hit in the area located above the sweet spot, known by some as the hot zone. The hot zone knocks rpms off the hit and sends the ball away on a higher trajectory for more penetrating and straighter shots. Give it a try and see if you can hit the hot zone.
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The impact between bat and ball is an extremely violent one, in which the bat imparts a huge force on the ball thereby causing it to change directions and gain speed. Consider a baseball weighing 5.125oz (mass = 0.145kg) which approaches the bat at a speed of 90mph (40.2m/s).
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A golf ball is hit with an initial speed of 35m/s at an angle less the 45 degrees above the horizontal.(A)The horizontal velocity componentis (1) greater than,(2) equal to or (3) less than the vertical velocity component.Why?
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They are standing 45 feet apart, and Lily throws the ball with an initial speed of 70 feet per second at an angle of 11 degrees (above the horizontal). When Lily releases the ball, it is 5 Answer. Given v = 20ms−1,θ = 30o,H = 45m. a. As the ball has been projected at an angle of 30o above horizontal, so first of all we need to analyse the velocity horizontally and vertically. This will be useful while using distance-time relation in horizontal and vertical directions. vxi.
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velocity of 6.00 m/s at an angle of 45.0 below the horizontal collides at point A with a 1.00-kg puck traveling to the right at a velocity of 3.00 m/s at an angle of 45.0 above the horizontal, as shown below. After the collision, the 2.0-kg puck moves toward the right at a velocity of 4.50 m/s at an angle of 25.0 below the horizontal.
• A 45 degree angle gives you the maximum distance to the point where the ball first hits the ground. That's not where a baseball will stop. If you hit the ball at a lower angle, more of the total speed will be in the horizontal direction, and the ball will still continue with a fairly high horizontal speed after bouncing. A baseball player hits a home run, and the ball lands in the left-field seats, 7.5 m above the point at which it was hit. It lands with a velocity of 36 m/s at an angle of 28° below the horizontal (see Figure 3.13). Ignoring air resistance, find the initial velocity with which the ball leaves the bat.